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25x^2+125x+150=0
a = 25; b = 125; c = +150;
Δ = b2-4ac
Δ = 1252-4·25·150
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(125)-25}{2*25}=\frac{-150}{50} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(125)+25}{2*25}=\frac{-100}{50} =-2 $
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